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Figure 1. Two pucks collide on an air table. |
Figure 1 shows two pucks colliding on an air table. An air table provides a cushion of air and reduces friction. Both the x and y directions, in this video, are real world horizontal. The video was taken using a tripod with the camera pointed down at the air table.
During the interaction (collision), the large puck applies a force on the small puck and the small puck applies a force on the large puck. If friction is sufficiently reduced on the air table and the air table is level, then these forces will be the only important forces. Therefore, the only important force on the large puck will come from the small puck and the only important force on the small puck will come from the large puck.
See the E1400 series of video experiments for a more detailed discussion on Newton's Third Law.
Newton's Third Law:
If Object 1 applies a force on Object 2, then Object 2 applies an equal and opposite force on Object 1. These forces are called action reaction pairs and have these characteristics:
If Newton's Third Law is true and all other forces acting are not important, then:
F1x = -F2x and F1y = -F2y
Since force is the slope of a momentum-versus-time graph, this means that the slope of Object 1's momentum-versus-time graph should equal the negative slope of Object 2's momentum-versus-time graph during the interaction. Notice that these conditions are met in both the x and y directions.
Dp1x = -Dp2x and Dp1y = -Dp2y
Graphically, if one object's momentum changes by a certain value, then the other object's momentum will change by the negative of this value. Notice that these conditions are met in both the x and y directions.
DpTx = 0 and DpTy = 0
A plot of the total momentum versus time should be a horizontal line (zero slope). Again, notice that these conditions are met in both the x and y directions.
Finally, does the above discussion say the following?
You should prove or disprove these last three statements while analyzing the video experiments.
Table 1 below shows how to find the magnitude and direction for acceleration, net force and impulse. You can add the additional subscripts 1 or 2 for the two different objects, but do not mix these subscripts in the same table. After finding the x and y components, the magnitude is the square root of the sum of the squares, and the direction is the inverse tangent of the y component divided by the x component in the correct quadrant.
Table 1. Two dimensional equations for acceleration, net force and impulse.
x direction | y direction | magnitude | direction |
ax= Dvx/Dt | ay= Dvy/Dt | (ax2 + ay2)0.5 | tan-1(ay/ax) |
Fx= Dpx/Dt | Fy= Dpy/Dt | (Fx2 + Fy2)0.5 | tan-1(Fy/Fx) |
Dpx | Dpy | (Dpx2 + Dpy2)0.5 | tan-1(Dpy/Dpx) |
After finding the resultant acceleration, force and impulse on each object, you can determine if Newton's Third Law is true.
Remember:
Acceleration is the slope of a velocity-versus-time graph. In two dimensions, there may be two accelerations. You must find the acceleration in the x direction (ax) and in the y direction (ay).
Net force is the slope of a momentum-versus-time graph. In two dimensions, there may be two net forces. You must find the net forces in the x direction (Fx) and in the y direction (Fy).
Dp is the change in momentum. In two directions, you must find both Dpx and Dpy.